\( 145 = 5 (10 + 9d) \)

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• Sum formula: \( S_n = \frac{n}{2} (2a + (n-1)d) \)
• Here, \( S_{10} = 145 \), \( a = 5 \), \( n = 10 \)
• \( 145 = \frac{10}{2} (2 \times 5 + 9d) \)
• \( 145 = 50 + 45d \)
• \( 95 = 45d \)
• \( d = \frac{95}{45} = \frac{19}{9} \approx 2.11 \)

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