A car accelerates from rest at a constant rate of \( 3 \, \text{m/s}^2 \). How far does it travel in 10 seconds?

["# How Far Does a Car Travel When Accelerating from Rest?", "Understanding the motion of a vehicle acceleration is a fundamental concept in physics. When a car starts from rest and accelerates uniformly, its distance traveled can be calculated using the equations of motion. In this article, we explore the scenario where a car accelerates at a constant rate of (3 , \ ext{m/s}^2) and determine how far it travels in 10 seconds.", "## The Physics Behind Uniform Acceleration", "When an object begins from rest ((u = 0)) and accelerates at a constant rate ((a)), its distance (s) traveled in time (t) is given by the kinematic equation:", "[\ns = ut + \frac{1}{2} a t^2\n]", "Since the initial speed (u = 0), the equation simplifies to:", "[\ns = \frac{1}{2} a t^2\n]", "### Given Values\n- Acceleration (a = 3 , \ ext{m/s}^2)\n- Time (t = 10 , \ ext{seconds})", "### Substituting into the Formula", "[\ns = \frac{1}{2} \ imes 3 , \ ext{m/s}^2 \ imes (10 , \ ext{s})^2\n]", "[\ns = \frac{1}{2} \ imes 3 \ imes 100 = \frac{300}{2} = 150 , \ ext{meters}\n]", "## Conclusion", "In 10 seconds, a car accelerating uniformly from rest at (3 , \ ext{m/s}^2) travels exactly 150 meters. This calculation demonstrates how constant acceleration translates directly into measurable distance over time, a principle widely applied in vehicle design, traffic physics, and motion analysis.", "---", "### Tips for Studying Constant Acceleration", "- Always begin with (u = 0) when starting from rest.\n- Use (s = \frac{1}{2} a t^2) for constant acceleration.\n- Double-check units to ensure consistency.\n- Apply this formula to real-world problems like car crashes, sports momentum, and robotics.", "Understanding these basics empowers you to solve more complex motion problems and supports your journey in physics or engineering."]