Así, la región válida es un trapecio desde $ X = 0 $ hasta $ X = 45 $, con altura constante en $ Y $ desde $ X+15 $ hasta 60.
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- Cuando $ X = 0 $, $ Y \geq 15 $
- Cuando $ X = 45 $, $ Y \geq 60 $
- Para $ X > 45 $, $ Y \geq X + 15 > 60 $, lo cual está fuera del cuadrado
- Área de esta región:
- \int_0^{45} (60 - (X + 15))\, dX = \int_0^{45} (45 - X)\, dX = \left[45X - \frac{X^2}{2}\right]_0^{45} = 45 \cdot 45 - \frac{45^2}{2} = 2025 - \frac{2025}{2} = \frac{2025}{2}
- Así, el área favorable es $ \frac{2025}{2} $. El área total es 3600, entonces:
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