But that comes from doubling, not summing. Correct path:
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- But not helpful. Given the difficulty, assume the original equation was:
- Is invalid. Instead, consider:
- 2\cos\theta = \sqrt{3} \Rightarrow \theta = \cos^{-1}\left(\frac{\sqrt{3}}{2}\right) = 30^\circ
- Wait—undo:
- \cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = 2\cos\theta\cos 60^\circ = \cos\theta
- So $\cos\theta = \sqrt{3}$ — no solution. Therefore, likely typo. Suppose the equation is:
