D \cup W = D + W - D \cap W

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• Let \( D = 45 \) be number of deer, \( W = 38 \) be wolves, and \( D \cap W \) be those that are both.
• Total animals: \( D \cup W = 72 \).
• By inclusion-exclusion:
• = 45 + 38 - D \cap W
• = 83 - D \cap W
• D \cap W = 83 - 72 = 11

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