h(2) = 2(2) + 1 = 5
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- Solution: First compute $g(3)$:
- g(3) = 3^2 - 4(3) + 5 = 9 - 12 + 5 = 2
- Then compute $h(g(3)) = h(2)$:
- Final answer: $\boxed{5}$
- Question: A sequence of five real numbers forms an arithmetic progression with the first term $a$ and common difference $d$. If the sum of the first and third terms is 14, and the second term is 5, find the fifth term.
- Solution: The terms are $a$, $a + d$, $a + 2d$, $a + 3d$, $a + 4d$.
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