Setting the diagonal equal to the diameter of the circle, we have:
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- An inscribed square within a circle implies that the diagonal of the square is equal to the diameter of the circle. The diameter of the circle is \(2 \times 5 = 10\) units.
- Let the side length of the square be \(s\). The diagonal of the square is given by the formula:
- \text{Diagonal} = s\sqrt{2}
- s\sqrt{2} = 10
- Solving for \(s\), we divide both sides by \(\sqrt{2}\):
- s = \frac{10}{\sqrt{2}} = 5\sqrt{2}
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