Solution: Let $ \sqrt{x} = y $, so $ x = y^2 $. Substituting into the equation gives:
Related Articles
- Substituting \(s = 6\), we have:
- R = \frac{6}{\sqrt{3}} = 2\sqrt{3}
- Therefore, the radius of the circumscribed circle is \(\boxed{2\sqrt{3}}\).Question: A computational biologist is analyzing a dataset of genetic sequences and encounters the equation $ x\sqrt{x} - 5x + 6\sqrt{x} = 0 $. Compute the sum of all real, non-negative roots of this equation.
- y^2 \cdot y - 5y^2 + 6y = 0 \Rightarrow y^3 - 5y^2 + 6y = 0
- Factor out $ y $:
- y(y^2 - 5y + 6) = 0 \Rightarrow y(y - 2)(y - 3) = 0
Trending Articles
Monopoly Rent Rush: Can You Still Buy Park Place
Metal Gear Solid 3: Snake Eater Master Collection - The Version Fans Are Losing Their Minds Over
Rent Rush Monopoly: The Tactic No One Talks About
Metal Gear Solid 3 Snake Eater Master Collection Version Comparison Shocking Truth
Unlock The Legendary Version Secrets Hidden In Metal Gear Solid 3 Snake Eater Master Collection
Is The Master Collection Version Finally The Perfect Way To Play Snake Eater?
Ready, Set, Find: The Missing Letter L Game
The Secret 'You & Me' ARG on Reddit Everyone is Missing
Unlock the Secret Bones of MTG's Cowboy Bebop Set
Is MTG's Next Expansion a Cowboy Bebop Dream?